For which of the following types of ions is the number of unpaired electrons in octahedral complexes fixed at the same number as in the free ion,no matter how weak or strong the crystal field is?

  • A
    $d^3$
  • B
    $d^4$
  • C
    $d^5$
  • D
    $d^6$

Explore More

Similar Questions

In an octahedral crystal field,the $t_{2g}$ orbitals are:

For which of the following pairs of complexes is the crystal field splitting energy $\Delta_0$ for $II > \Delta_0$ for $I$?
$I$ $II$
$(a). [Cr(H_2O)_6]^{2+}$ $[Cr(H_2O)_6]^{3+}$
$(b). [Fe(H_2O)_6]^{3+}$ $[Fe(CN)_6]^{3-}$
$(c). [Fe(CN)_6]^{3-}$ $[Ru(CN)_6]^{3-}$
$(d). [NiF_6]^{4-}$ $[NiF_6]^{2-}$

Difficult
View Solution

The crystal field stabilization energy of $[Co(NH_3)_6]Cl_3$ is $......... \Delta_0$

Consider the following complexes:
$[CoCl(NH_3)_5]^{2+},$ $[Co(CN)_6]^{3-}$
$(A)$ $(B)$
$[Co(NH_3)_5(H_2O)]^{3+},$ $[Cu(H_2O)_4]^{2+}$
$(C)$ $(D)$
The correct order of $A, B, C,$ and $D$ in terms of the wavenumber of light absorbed is:

The number of complexes from the following with no electrons in the $t_{2g}$ orbital is: $TiCl_4, [MnO_4]^{-}, [FeO_4]^{2-}, [FeCl_4]^{-}, [CoCl_4]^{2-}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo